public class MaterialInfo
{
string _id;
string _name;
public stirng ID
{
get{....}
set{....}
}
public string Name
{
get{....}
set{....}
}
}public class A
{
string _id;
MaterialInfo _material;
public stirng ID
{
get{....}
set{....}
}
public MaterialInfo Material
{
get{....}
set{....}
}
}在winform中如何绑定数据.
假设 A.ID=1;
A.Material.ID = "00001";
A.Material.Name = "物料名称";
如何将数据绑定到DataGrid或是DataGridView得到一行数据(1,00001,物料名称1).
DataGrid是否直接支持,如果支持怎么做。
要是不支持,有什么好的方法解决这个问题?
{
string _id;
string _name;
public stirng ID
{
get{....}
set{....}
}
public string Name
{
get{....}
set{....}
}
}public class A
{
string _id;
MaterialInfo _material;
public stirng ID
{
get{....}
set{....}
}
public MaterialInfo Material
{
get{....}
set{....}
}
}在winform中如何绑定数据.
假设 A.ID=1;
A.Material.ID = "00001";
A.Material.Name = "物料名称";
如何将数据绑定到DataGrid或是DataGridView得到一行数据(1,00001,物料名称1).
DataGrid是否直接支持,如果支持怎么做。
要是不支持,有什么好的方法解决这个问题?
使用时转换回来就行
al.add("你的Class");
...
你建一个DataGrid是可以这样的DataGrid.DataSource = al;或是等于你的Class数组.
{
if (this.dataGridView1.Columns["ContactName"].Index ==
e.ColumnIndex && e.RowIndex >= 0)
{
this.DataGridView.Rows[e.RowIndex][e.ColumnIndex].Tag = A(你的值_)
}
}
DataGridViewCell.Tag 值怎么写
不知道DataGrid能不能用这种方法.
{
string _id;
MaterialInfo _material;
public stirng ID
{
get{....}
set{....}
}
public MaterialInfo Material
{
set{....}//这里设置成只写
} //另外增加两个只读属性
public string MaterialInforID
{
get{return _material.id;}
}
public string MaterialName
{
get{return _material.name;}
}
}这样非嵌套的对象绑定,楼主应该知道...
{
private BindingSource bs = new BindingSource();
public Form1()
{
InitializeComponent();
} private void button1_Click(object sender, EventArgs e)
{
bs.Add(new A("111", new MaterialInfo("111", "aaa")));
bs.Add(new A("222", new MaterialInfo("222", "bbb")));
this.dataGridView1.DataSource = bs;
}
}
public class MaterialInfo
{
string _id;
string _name; public MaterialInfo(string id, string name)
{
this._id = id;
this._name = name;
}
public string ID
{
get { return this._id; }
set { this._id = value; }
} public string Name
{
get { return this._name; }
set { this._name = value; }
}
}
public class A
{
string _id;
MaterialInfo _material; public A(string id, MaterialInfo material)
{
this._id = id;
this._material = material;
}
public string ID
{
get { return this._id; }
set { this._id = value; }
} public MaterialInfo Material
{
set { this._material = value; }//这里设置成只写
} //另外增加两个只读属性
public string MaterialInforID
{
get { return _material.ID; }
}
public string MaterialName
{
get { return _material.Name; }
}
}
snowlover的方法应该是很好的解决方法了.